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福建省2024届高三下学期3月适应性练习卷数学试题(PDF版含答案)

日期:2024-06-24 科目:数学 类型:高中试卷 查看:20次 大小:2806973Byte 来源:二一课件通
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福建省,2024届,高三下,三下,学期,3月
    2024 届高中毕业班适应性练习卷 数学参考答案及评分细则 评分说明: 1.本解答给出了一种或几种解法供参考,如果考生的解法与本解答不同,可根据试题的主要考查内 容比照评分标准制定相应的评分细则. 2.对计算题,当考生的解答在某一步出现错误时,如果后继部分的解答未改变该题的内容和难度, 可视影响的程度决定后继部分的给分,但不得超过该部分正确解答应给分数的一半;如果后继部分的解答 有较严重的错误,就不再给分. 3.解答右端所注分数,表示考生正确做到这一步应得的累加分数. 4.只给整数分数.选择题和填空题不给中间分. 一、选择题:本大题考查基础知识和基本运算.每小题 5 分,满分 40 分. 1.B 2.D 3.A 4.C 5.A 6.C 7.B 8.B 二、选择题:本大题考查基础知识和基本运算.每小题 6 分,满分 18 分.全部选对的得 6 分,部分选对 的得部分分,有选错的得 0 分. 9.AD 10.ABD 11.BCD 三、填空题:本大题考查基础知识和基本运算.每小题 5 分,满分 15 分. 12.0.2718 13.56π;80π 73(仅答对一空给 3 分) 14. 5 四、解答题:本大题共 5 小题,共 77 分.解答应写出文字说明、证明过程或演算步骤. 15.本小题主要考查正弦定理、余弦定理等基础知识,考查逻辑推理能力、运算求解能力等,考查化归与 转化思想、函数与方程思想、数形结合思想等,考查数学运算、逻辑推理等核心素养,体现基础性和 综合性.满分 13 分. 解法一:(1)由∠DAC + ∠BAC = π,可得 sin ∠BAC = sin ∠DAC . ··············································· 1 分 AB BC 在△ABC 中,由正弦定理,得 = , ···························································· 3 分 sin C sin ∠BAC A 所以 AB BC sin C = . sin ∠BAC AD CD 在△ADC 中,由正弦定理,得 = , ···············B··················D·················C········· 5 分 sin C sin ∠DAC AD CDsin C 所以 = . sin ∠DAC AB BC 故 = . ············································································································· 6 分 AD CD BC AB 因为 D 为 BC 的中点,所以 =2 ,即 =2 . ································································ 7 分 CD AD (2)由(1)不妨设 AD = x , AB = 2x , AC = y, BC = 2 2y . ················································· 8 分 ( 2y)2 + y2 x2 在△ADC 中,由余弦定理,得 cosC = . ······················································ 9 分 2 × 2y × y 2 2 2 在△ABC 中,由余弦定理,得 cosC (2 2y) + y (2x) = . ················································ 10 分 2× 2 2y × y (2 2y)2 + y2 (2x)2 ( 2y)2 + y2 x2 所以 = . ···································································· 11 分 2× 2 2y × y 2× 2y × y 2 3 2 解得 x = y . ···································· ... ...

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